In Previous post we saw two dates in the year 2100 which is a century year and also a non leap year. In this post we will see two dates examples in the year 200 which is a century year and a leap year as well.

Last two digits from 2000 forms number 00. So, we will check if first two digits in year 2000 i.e. 20 is completely divisible by 4 i.e. remainder is zero if 20 is divided by 4 (or we will check if 20 is present in the multiplication table of 4).

**Example 7. 29**^{th}February 2000**Step 1.**Note down the date: 29**Step 2.**Note down the key number for month:__4__letters in January & February are common i.e. “uary”. Therefore, key number for Febr__uary__is__4__… (See Key Numbers For Months: 1^{st}Group)**Step 3.**Find and note down the key number for first two digits in year: First two digits from 2000 forms 20. Key number for 16 is 0, 17 is 5, 18 is 3, 19 is 1. The above sequence will repeat again. So, for 20 it will be 0…**Step 4.**Find and note down the key number for last two digits in year: Last two digits from 2000 forms 00. We know that**if we get a year in the format YY00 i.e. if last two digits form 00 then****key number for 00 will always be -1.****Step 5.**Add all the above noted numbers: 29 + 4 + 0 + (-1) = 32.**Step 6.**Divide above addition by 7 and find the remainder. If we divide 32 by 7 then we get 4 as a remainder.**Step 7.**Check if the year is a leap year or not (only if the given date falls in between 1^{st}January to 29^{th}February, both the dates including): As given date i.e. 29^{th}February 2000 falls in between 1^{st}January to 29^{th}February we need to check if the year 2000 is a leap year or not.Last two digits from 2000 forms number 00. So, we will check if first two digits in year 2000 i.e. 20 is completely divisible by 4 i.e. remainder is zero if 20 is divided by 4 (or we will check if 20 is present in the multiplication table of 4).

4 x 5 = 20

So, we can conclude that 20 is completely divisible by
4. And hence the year

2000 is a leap year.

**Step 8.**If the given date falls in between 1

^{st}January to 29

^{th}February and the year is a leap year then we need to go one day back from our calculated final day to get exact day.. So from Step 6 our final day would be Wednesday (As 4 points to Wednesday). But, for this case we need to go one day back from our calculated final day to get exact day.. So, our final day would be one day before Wednesday i.e. Tuesday…!!

**Example 8. 20**

^{th}September 2000**Step 1.**Note down the date: 20

**Step 2.**Note down the key number for month: In Latin Septem means. We will subtract

__1__from 7 and we get

__6__i.e. key number for September… (See Key Numbers For Months: 3

^{rd}Group)

**Step 3.**Find and note down the key number for first two digits in year: First two digits from 2000 forms 20 and we have already found the key number for 20 as 0 in previous example.

**Step 4.**Find and note down the key number for last two digits in year: Last two digits from 2000 forms 00. And we have found the key number for 00 as -1 in previous example.

**Step 5.**Add all the above noted numbers: 20 + 6 + 0 + (-1) = 25.

**Step 6.**Divide above addition by 7 and find the remainder. If we divide 25 by 7 then we get 4 as a remainder.

**Step 7.**Check if the year is a leap year or not (only if the given date falls in between 1

^{st}January to 29

^{th}February, both the dates including): As given date i.e. 20

^{th}September 2000 does not fall in between 1

^{st}January to 29

^{th}February we don’t need to check if the year 2000 is a leap year or not. So, 4 is our final result. And therefore 4 points to Wednesday i.e. the day of week on 20

^{th}September 2000 …!!

## No comments :

## Post a Comment